On the Difference Equationxn+1=xnxn−2− 1

Candace M. Kent; Witold Kosmala; Stevo Stević

doi:10.1155/2011/815285

ScienceGate Book Chapters

JOURNAL ARTICLE

On the Difference Equationx_n+1=x_nx_n−2− 1

Candace M. Kent Witold Kosmala Stevo Stević

Year: 2011 Journal: Abstract and Applied Analysis Vol: 2011 (1) Publisher: Hindawi Publishing Corporation

DOI: 10.1155/2011/815285

Get Full-Text PDF Get Analytical Report

Abstract

The long‐term behavior of solutions of the following difference equation: x n +1 = x n x n −2 − 1, n ∈ ℕ 0 , where the initial values x −2 , x −1 , x 0 are real numbers, is investigated in the paper.

Keywords:

Mathematics Combinatorics

Metrics

Cited By

4.53

FWCI (Field Weighted Citation Impact)

Refs

0.92

Citation Normalized Percentile

Is in top 1%

Is in top 10%

Citation History

Topics

Mathematical and Theoretical Epidemiology and Ecology Models

Health Sciences → Medicine → Public Health, Environmental and Occupational Health

Nonlinear Differential Equations Analysis

Physical Sciences → Mathematics → Applied Mathematics

Advanced Differential Equations and Dynamical Systems

Physical Sciences → Mathematics → Geometry and Topology

On the Difference Equationx_n+1=x_nx_n−2− 1

Abstract

Metrics

Citation History

Topics

Related Documents

Studies on the difference equationx_n+1 = 1/(x_n+x_n − 2)

Solutions of the Difference Equation x_n+1 = x_nx_n−1 − 1

On the difference equationx_n₊₁=Af(x_n) +f(x_n₋₁)

On the Difference Equation x_n = a_nx_n−k/(b_n + c_nx_n−1 ⋯ x_n−k)

On the Difference Equation x_n+1 = x_nx_n−k/(x_n−k+1(a + bx_nx_n−k))

On the Difference Equationxn+1=xnxn−2− 1

Abstract

Metrics

Citation History

Topics

Related Documents

Studies on the difference equationxn+1 = 1/(xn+xn − 2)

Solutions of the Difference Equation xn+1 = xnxn−1 − 1

On the difference equationxn+1=Af(xn) +f(xn−1)

On the Difference Equation xn = anxn−k/(bn + cnxn−1 ⋯ xn−k)

On the Difference Equation xn+1 = xnxn−k/(xn−k+1(a + bxnxn−k))

On the Difference Equationx_n+1=x_nx_n−2− 1

Studies on the difference equationx_n+1 = 1/(x_n+x_n − 2)

Solutions of the Difference Equation x_n+1 = x_nx_n−1 − 1

On the difference equationx_n₊₁=Af(x_n) +f(x_n₋₁)

On the Difference Equation x_n = a_nx_n−k/(b_n + c_nx_n−1 ⋯ x_n−k)

On the Difference Equation x_n+1 = x_nx_n−k/(x_n−k+1(a + bx_nx_n−k))